A is twice as fast as B and B is twice as fast as C. If they together can complete a work in 4 days, in how many days can C alone complete it? MCQ with Answer and Explanation
A is twice as fast as B and B is twice as fast as C. If they together can complete a work in 4 days, in how many days can C alone complete it?
A. 24 days
B. 32 days
C. 16 days
D. 28 days
Answer: Option D
Solution (By JKSSB Mock Tests)
Let efficiency of C = 1, then B = 2 and A = 4. Combined efficiency = 1 + 2 + 4 = 7 units/day. Total work = 4 * 7 = 28 units. Time taken by C alone = 28 / 1 = 28 days.
A can do a piece of work in 15 days and B in 20 days. They began the work together but A left after 4 days. In how many days will B complete the remaining work?
Explanation:
Total work = LCM(15, 20) = 60 units. Efficiency of A = 4, B = 3. Combined efficiency = 7. In 4 days, work completed = 4 * 7 = 28 units. Remaining work = 60 - 28 = 32 units. Time taken by B to complete remaining work = 32 / 3 = 10(2/3) days.
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