A is twice as fast as B and B is twice as fast as C. If they together can complete a work in 4 days, in how many days can C alone complete it? MCQ with Answer and Explanation
A is twice as fast as B and B is twice as fast as C. If they together can complete a work in 4 days, in how many days can C alone complete it?
A. 24 days
B. 28 days
C. 32 days
D. 16 days
Answer: Option B
Solution (By JKSSB Mock Tests)
Let efficiency of C = 1, then B = 2 and A = 4. Combined efficiency = 1 + 2 + 4 = 7 units/day. Total work = 4 * 7 = 28 units. Time taken by C alone = 28 / 1 = 28 days.
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