A body of mass 2 kg has momentum 10 kg m/s. Its kinetic energy is MCQ with Answer and Explanation

A body of mass 2 kg has momentum 10 kg m/s. Its kinetic energy is
A. 50 J
B. 20 J
C. 5 J
D. 25 J
Answer: Option D
Solution (By JKSSB Mock Tests)
Kinetic energy K = p²/(2m) = (10)²/(2×2) = 100/4 = 25 J. Also, velocity v = p/m = 5 m/s, K = ½×2×5² = 25 J. Formula p²/(2m) is useful for quick computation. Always ensure units: kg, m/s, J.

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Practice More Physics Questions

Question #1
A body falls freely from rest. The ratio of distances covered in 1st, 2nd, and 3rd seconds is
A. 1:2:3
B. 1:1:1
C. 1:4:9
D. 1:3:5

Correct Answer: Option D


Explanation:
s_nth = u + (g/2)(2n-1). u=0 => s ∝ (2n-1). So 1, 3, 5. Classic kinematic ratio.

This question belongs to: Science Physics
Question #2
The relation V = IR is applicable to
A. Semiconductors
B. Ohmic conductors
C. Non-ohmic devices
D. Gaseous conductors

Correct Answer: Option B


Explanation:
Ohm's law V=IR is linear relationship, valid for ohmic materials like metals at constant temperature. Non-ohmic do not follow linear I-V. Semiconductors are non-ohmic.

This question belongs to: Science Physics
Question #3
A ball is dropped from a height of 20 m. Time to reach ground (g=10) is
A. 4 s
B. 2 s
C. 3 s
D. 1 s

Correct Answer: Option B


Explanation:
h = ½gt² => t = √(2h/g) = √(40/10) = √4 = 2 s. Free fall formula. Final velocity v = gt = 20 m/s.

This question belongs to: Science Physics