A car accelerates uniformly from rest to a speed of 72 km/h in 10 seconds. What is the distance covered during this time? MCQ with Answer and Explanation

Question

A car accelerates uniformly from rest to a speed of 72 km/h in 10 seconds. What is the distance covered during this time?

A. 200 m

B. 400 m

C. 100 m

D. 720 m

Answer: Option C

Solution (By JKSSB Mock Tests)

First, convert speed to SI units: 72 km/h = 72 × (5/18) m/s = 20 m/s. Initial velocity (u) = 0, final velocity (v) = 20 m/s, time (t) = 10 s. Acceleration (a) = (v-u)/t = 20/10 = 2 m/s². Distance (s) = ut + (1/2)at² = 0 + 0.5 × 2 × 10² = 100 meters.

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The process of emission of electrons from hot metal surface is called

A. Photoelectric emission

B. Field emission

C. Secondary emission

D. Thermionic emission

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Correct Answer: Option D

Explanation:
Thermionic emission: electrons emitted when metal heated to high temperature (e.g., filament in cathode ray tube). Photoelectric: light incident. Field emission: strong electric field. Secondary: bombardment by particles.

This question belongs to: Science Physics