A car decelerates uniformly from 20 m/s to rest in 4 s. Distance covered is MCQ with Answer and Explanation

A car decelerates uniformly from 20 m/s to rest in 4 s. Distance covered is
A. 20 m
B. 60 m
C. 40 m
D. 80 m
Answer: Option C
Solution (By JKSSB Mock Tests)
a = (0-20)/4 = -5 m/s². s = 20×4 + ½(-5)×16 = 80 - 40 = 40 m. Or average velocity 10 m/s × 4 = 40 m.

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