A driver spans a highway path of 400 km. If the uniform speed is boosted by 10 km/h, the trip wraps up in 2 hours less. Find the initial speed. MCQ with Answer and Explanation

Explanation:
Time = 5 hours 20 minutes = 5 + 20/60 = 5.333 hours = 16/3 hours. Speed index = Sector Distance / Time = 480 / (16/3) = 480 * 3 / 16 = 30 * 3 = 90 km/h.

Explanation:
Distance covered in 1 revolution = 880 / 1000 = 0.88 meters = 88 cm. Circumference = 2 * (22/7) * r = 88 cm => (44/7) * r = 88 => r = 14 cm. Diameter = 2r = 28 cm.

Explanation:
New speed = 8/9 of usual speed => New time = 9/8 of usual time. Difference = 1/8 of usual time = 12 minutes. Usual time = 12 * 8 = 96 minutes.