A driver spans a highway path of 400 km. If the uniform speed is boosted by 10 km/h, the trip wraps up in 2 hours less. Find the initial speed. MCQ with Answer and Explanation

Question

A driver spans a highway path of 400 km. If the uniform speed is boosted by 10 km/h, the trip wraps up in 2 hours less. Find the initial speed.

A. 40 km/h

B. 45 km/h

C. 35 km/h

D. 50 km/h

Answer: Option A

Solution (By JKSSB Mock Tests)

Let original speed be s. 400/s - 400/(s+10) = 2 => 200/s - 200/(s+10) = 1 => 2000 = s(s+10). Solving s^2 + 10s - 2000 = 0 yields (s-40)(s+50) = 0. Speed = 40 km/h.

This question belongs to: Maths Time Speed and Distance

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Question #1

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A cyclist covers 900 meters in exactly 3 minutes. Find his speed in km/h.

A. 22 km/h

B. 18 km/h

C. 16 km/h

D. 20 km/h

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Correct Answer: Option B

Explanation:
Time = 3 minutes = 180 seconds. Speed = 900 / 180 = 5 m/s. In km/h = 5 * (18/5) = 18 km/h.

This question belongs to: Maths Time Speed and Distance

Question #2

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Excluding stoppages, the speed of a bus is 45 km/h and including stoppages it is 36 km/h. For how many minutes does the bus stop per hour?

A. 10 minutes

B. 14 minutes

C. 15 minutes

D. 12 minutes

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Correct Answer: Option D

Explanation:
Stoppage time per hour = (45 - 36) / 45 = 9 / 45 = 1/5 hour. In minutes = (1/5) * 60 = 12 minutes.

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Question #3

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In a 500-meter dash trial heat, runner A clocks across the tape in 50 seconds, while runner B marks a finish layout in 55 seconds. By what distance does runner A beat runner B?

A. 50.00 meters

B. 45.45 meters

C. 42.34 meters

D. 48.25 meters

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Correct Answer: Option B

Explanation:
Speed of runner B = 500 / 55 = 100 / 11 m/s. Distance covered by runner B when runner A finishes at 50 seconds = (100 / 11) * 50 = 5000 / 11 = 454.54 meters. Margin distance = 500 - 454.54 = 45.45 meters.

This question belongs to: Maths Time Speed and Distance

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