A man covers 3/5 of his total journey by rail at 40 km/h and the remaining 2/5 by bus at 30 km/h. If the total distance is 150 km, what is the total time taken? MCQ with Answer and Explanation
A man covers 3/5 of his total journey by rail at 40 km/h and the remaining 2/5 by bus at 30 km/h. If the total distance is 150 km, what is the total time taken?
A. 4 hours
B. 4.5 hours
C. 4.25 hours
D. 5 hours
Answer: Option C
Solution (By JKSSB Mock Tests)
Distance by rail = 150 * (3/5) = 90 km. Time by rail = 90 / 40 = 2.25 hours. Distance by bus = 150 - 90 = 60 km. Time by bus = 60 / 30 = 2 hours. Total time = 2.25 + 2 = 4.25 hours.
Explanation:
When A covers 100m, B covers 80m. When B covers 100m, C covers 90m. Thus, when B covers 80m, C covers 90 * (80 / 100) = 72m. Therefore, when A covers 100m, C covers 72m. A beats C by 100 - 72 = 28 meters.
A suspect flees at 6:00 AM at a uniform speed of 50 km/h. The enforcement squad tracks pursuit at 7:00 AM at 60 km/h. At what time will the squad apprehend the suspect?
Explanation:
By 7:00 AM, the suspect has traveled for 1 hour and covered 50 km. Relative tracking speed = 60 - 50 = 10 km/h. Time taken to catch = 50 / 10 = 5 hours. Apprehension time = 7:00 AM + 5 hours = 12:00 PM.
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