A suspect flees at 6:00 AM at a uniform speed of 50 km/h. The enforcement squad tracks pursuit at 7:00 AM at 60 km/h. At what time will the squad apprehend the suspect? MCQ with Answer and Explanation

A suspect flees at 6:00 AM at a uniform speed of 50 km/h. The enforcement squad tracks pursuit at 7:00 AM at 60 km/h. At what time will the squad apprehend the suspect?
A. 11:00 AM
B. 1:00 PM
C. 12:00 PM
D. 2:00 PM
Answer: Option C
Solution (By JKSSB Mock Tests)
By 7:00 AM, the suspect has traveled for 1 hour and covered 50 km. Relative tracking speed = 60 - 50 = 10 km/h. Time taken to catch = 50 / 10 = 5 hours. Apprehension time = 7:00 AM + 5 hours = 12:00 PM.

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Practice More Time Speed and Distance Questions

Question #1
A train 150 meters long takes 20 seconds to cross a platform 250 meters long. Find the speed of the train in km/h.
A. 50 km/h
B. 64 km/h
C. 72 km/h
D. 80 km/h

Correct Answer: Option C


Explanation:
Total distance = 150 + 250 = 400 meters. Time = 20 seconds. Speed = 400 / 20 = 20 m/s. Speed in km/h = 20 * (18/5) = 72 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
A track sprinter matches a 300-meter straight heat in 30 seconds. Find his moving speed in km/h.
A. 32 km/h
B. 36 km/h
C. 44 km/h
D. 40 km/h

Correct Answer: Option B


Explanation:
Speed in m/s = 300 / 30 = 10 m/s. In km/h = 10 * (18/5) = 36 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3
A person travels from P to Q at a speed of 30 km/h and returns from Q to P at a speed of 40 km/h. What is the ratio of time taken by him in the forward journey to that in the return journey?
A. 9:16
B. 16:9
C. 3:4
D. 4:3

Correct Answer: Option D


Explanation:
Since distance is constant, time is inversely proportional to speed. Ratio of times = Speed2 : Speed1 = 40 : 30 = 4:3.

This question belongs to: Maths Time Speed and Distance