A man covers 50 km at a speed of 25 km/h and another 90 km at a speed of 30 km/h. Find his average speed for the whole journey. MCQ with Answer and Explanation

A man covers 50 km at a speed of 25 km/h and another 90 km at a speed of 30 km/h. Find his average speed for the whole journey.
A. 30 km/h
B. 28 km/h
C. 28.5 km/h
D. 26.5 km/h
Answer: Option B
Solution (By JKSSB Mock Tests)
Total distance = 50 + 90 = 140 km. Time for first part = 50 / 25 = 2 hours. Time for second part = 90 / 30 = 3 hours. Total time = 5 hours. Average speed = 140 / 5 = 28 km/h.

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Practice More Time Speed and Distance Questions

Question #1
A track sprinter matches a 300-meter straight heat in 30 seconds. Find his moving speed in km/h.
A. 36 km/h
B. 40 km/h
C. 32 km/h
D. 44 km/h

Correct Answer: Option A


Explanation:
Speed in m/s = 300 / 30 = 10 m/s. In km/h = 10 * (18/5) = 36 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
A man can row 6 km/h in still water. If the speed of the current is 2 km/h, it takes him 3 hours to row to a place and back. How far is the place?
A. 12 km
B. 8 km
C. 6 km
D. 10 km

Correct Answer: Option B


Explanation:
Downstream speed = 6 + 2 = 8 km/h. Upstream speed = 6 - 2 = 4 km/h. Let distance be d. d/8 + d/4 = 3 => (d + 2d)/8 = 3 => 3d/8 = 3 => d = 8 km.

This question belongs to: Maths Time Speed and Distance
Question #3
Two junction points M and N are separated by 300 km. Train P leaves M for N at 45 km/h at 8:00 AM. Train Q leaves N for M at 55 km/h at 9:00 AM. At what time will they cross?
A. 11:33 AM
B. 11:15 AM
C. 12:00 PM
D. 11:45 AM

Correct Answer: Option A


Explanation:
By 9:00 AM, Train P has tracked for 1 hour, covering 45 km. Remaining route segment gap separation = 300 - 45 = 255 km. Relative speed index = 45 + 55 = 100 km/h. Time after 9:00 AM = 255 / 100 = 2.55 hours = 2 hours 33 minutes. Meeting time is 11:33 AM.

This question belongs to: Maths Time Speed and Distance