A man starts walking from a place P at 4 AM at a speed of 5 km/h. Another man starts from the same place P at 6 AM in the same direction at a speed of 7 km/h. At what time will they meet? MCQ with Answer and Explanation
A man starts walking from a place P at 4 AM at a speed of 5 km/h. Another man starts from the same place P at 6 AM in the same direction at a speed of 7 km/h. At what time will they meet?
A. 10:00 AM
B. 1:00 PM
C. 12:00 PM
D. 11:00 AM
Answer: Option D
Solution (By JKSSB Mock Tests)
By 6:00 AM, the first man has traveled for 2 hours, covering 5 * 2 = 10 km. Relative speed = 7 - 5 = 2 km/h. Time to meet = 10 / 2 = 5 hours. Meeting time = 6:00 AM + 5 hours = 11:00 AM.
Explanation:
Total distance = 40 + 60 = 100 km. Time for first sector = 40 / 20 = 2 hours. Time for second sector = 60 / 30 = 2 hours. Total time = 4 hours. Average speed = 100 / 4 = 25 km/h.
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