A man starts walking from a place P at 4 AM at a speed of 5 km/h. Another man starts from the same place P at 6 AM in the same direction at a speed of 7 km/h. At what time will they meet? MCQ with Answer and Explanation
A man starts walking from a place P at 4 AM at a speed of 5 km/h. Another man starts from the same place P at 6 AM in the same direction at a speed of 7 km/h. At what time will they meet?
A. 11:00 AM
B. 12:00 PM
C. 10:00 AM
D. 1:00 PM
Answer: Option A
Solution (By JKSSB Mock Tests)
By 6:00 AM, the first man has traveled for 2 hours, covering 5 * 2 = 10 km. Relative speed = 7 - 5 = 2 km/h. Time to meet = 10 / 2 = 5 hours. Meeting time = 6:00 AM + 5 hours = 11:00 AM.
A person travels from P to Q at a speed of 30 km/h and returns from Q to P at a speed of 40 km/h. What is the ratio of time taken by him in the forward journey to that in the return journey?
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