A man walks at a speed of 6 km/h instead of 5 km/h and thereby covers 12 km more in the same duration. Find the actual distance covered by him at his normal speed. MCQ with Answer and Explanation
A man walks at a speed of 6 km/h instead of 5 km/h and thereby covers 12 km more in the same duration. Find the actual distance covered by him at his normal speed.
A. 80 km
B. 72 km
C. 50 km
D. 60 km
Answer: Option D
Solution (By JKSSB Mock Tests)
Let duration be t hours. Distance difference = 6t - 5t = t = 12 hours. Distance at normal speed (5 km/h) = 5 * 12 = 60 km.
Explanation:
By 7:00 AM, the first person covers 30 * 2 = 60 km. Relative speed = 40 - 30 = 10 km/h. Time to meet = 60 / 10 = 6 hours. Distance from A = Speed of second person * Time = 40 * 6 = 240 km.
A locomotive express train passes a milestone column track point in 15 seconds flat. If the speed index of the train records at 72 km/h, find the length of the train layout.
Explanation:
New speed = 4/5 of usual speed => New time = 5/4 of usual time. Difference = 1/4 of usual time = 12 minutes. Usual time = 12 * 4 = 48 minutes.
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