A man walks from his residence to a focal point at 4 km/h and arrives 10 minutes late. If he increases his speed to 5 km/h, he arrives 2 minutes early. Find the distance. MCQ with Answer and Explanation
A man walks from his residence to a focal point at 4 km/h and arrives 10 minutes late. If he increases his speed to 5 km/h, he arrives 2 minutes early. Find the distance.
A. 4.0 km
B. 3.5 km
C. 4.5 km
D. 5.0 km
Answer: Option A
Solution (By JKSSB Mock Tests)
Time difference = 10 - (-2) = 12 minutes = 12/60 = 0.2 hours. Let distance be d. d / 4 - d / 5 = 0.2 => d / 20 = 0.2 => d = 4 km.
A man leaves point A at 6 AM at a speed of 4 km/h. Another man leaves point A from the same direction at 8 AM at a speed of 6 km/h. At what distance from point A will they meet?
Explanation:
By 8 AM, the first man has traveled for 2 hours, covering 4 * 2 = 8 km. Relative speed = 6 - 4 = 2 km/h. Time taken to meet = 8 / 2 = 4 hours. Distance from A = Speed of second man * Time = 6 * 4 = 24 km.
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