A passenger train 200 meters long crosses a platform 300 meters long in 20 seconds. What is the speed of the train in km/h? MCQ with Answer and Explanation

A passenger train 200 meters long crosses a platform 300 meters long in 20 seconds. What is the speed of the train in km/h?
A. 100 km/h
B. 80 km/h
C. 110 km/h
D. 90 km/h
Answer: Option D
Solution (By JKSSB Mock Tests)
Total distance = 200 + 300 = 500 meters. Speed = 500 / 20 = 25 m/s. Converting to km/h = 25 * (18/5) = 90 km/h.

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Practice More Time Speed and Distance Questions

Question #1
A thief is spotted by a policeman from a distance of 250 meters. The thief runs at 11 km/h and the policeman chases him at 13 km/h. Find the distance covered by the thief before he is caught.
A. 1250 meters
B. 1375 meters
C. 1500 meters
D. 1625 meters

Correct Answer: Option B


Explanation:
Relative speed = 13 - 11 = 2 km/h. Time to catch the thief = 0.25 km / 2 km/h = 0.125 hours. Distance covered by thief = Speed * Time = 11 km/h * 0.125 hours = 1.375 km = 1375 meters.

This question belongs to: Maths Time Speed and Distance
Question #2
A train running at 54 km/h crosses a bridge 150 meters long in 18 seconds. Find the length of the train.
A. 150 meters
B. 140 meters
C. 100 meters
D. 120 meters

Correct Answer: Option D


Explanation:
Speed = 54 * (5/18) = 15 m/s. Total distance in 18 seconds = 15 * 18 = 270 meters. Length of train = 270 - 150 = 120 meters.

This question belongs to: Maths Time Speed and Distance
Question #3
A car covered a distance of 400 km at a uniform speed. If the uniform speed index is lowered by 10 km/h, the journey takes 2 hours longer. Find the original speed.
A. 45 km/h
B. 55 km/h
C. 60 km/h
D. 50 km/h

Correct Answer: Option D


Explanation:
Let original speed be s. 400 / (s - 10) - 400 / s = 2 => 200 / (s - 10) - 200 / s = 1 => 2000 = s(s - 10). Solving s^2 - 10s - 2000 = 0 yields (s - 50)(s + 40) = 0. Original speed = 50 km/h.

This question belongs to: Maths Time Speed and Distance