A person runs along the sides of an equilateral triangular field at speeds of 10 km/h, 15 km/h and 30 km/h respectively. Find his average speed for the entire perimeter. MCQ with Answer and Explanation

A person runs along the sides of an equilateral triangular field at speeds of 10 km/h, 15 km/h and 30 km/h respectively. Find his average speed for the entire perimeter.
A. 12 km/h
B. 18 km/h
C. 20 km/h
D. 15 km/h
Answer: Option D
Solution (By JKSSB Mock Tests)
Let each side of the triangular field be 30 km (LCM of 10, 15, 30). Total distance = 3 * 30 = 90 km. Total time taken = 30/10 + 30/15 + 30/30 = 3 + 2 + 1 = 6 hours. Average speed = 90 / 6 = 15 km/h.

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Practice More Time Speed and Distance Questions

Question #1
A mechanical wheel has a radius of 7 cm. How many revolutions are required to cover a linear distance of 44 meters?
A. 120
B. 150
C. 100
D. 80

Correct Answer: Option C


Explanation:
Circumference of the wheel = 2 * (22/7) * 7 = 44 cm = 0.44 meters. Total distance = 44 meters. Number of revolutions = 44 / 0.44 = 100.

This question belongs to: Maths Time Speed and Distance
Question #2
A train 140 meters long tracking at 63 km/h passes a modern bridge in 24 seconds. Find the length of the bridge.
A. 320 meters
B. 280 meters
C. 260 meters
D. 300 meters

Correct Answer: Option B


Explanation:
Speed of train = 63 * (5/18) = 17.5 m/s. Total distance handled in 24 seconds = 17.5 * 24 = 420 meters. Length of the bridge = 420 - 140 = 280 meters.

This question belongs to: Maths Time Speed and Distance
Question #3
A train 150 meters long completely passes a station pole sign in 6 seconds flat. Find its speed in km/h.
A. 80 km/h
B. 100 km/h
C. 90 km/h
D. 110 km/h

Correct Answer: Option C


Explanation:
Speed of train = 150 / 6 = 25 m/s. Converting to km/h = 25 * (18/5) = 90 km/h.

This question belongs to: Maths Time Speed and Distance