A person walks from his home to his office at 4.5 km/h and reaches 12 minutes late. If he walks at 6 km/h, he reaches 3 minutes early. Find the distance. MCQ with Answer and Explanation
A person walks from his home to his office at 4.5 km/h and reaches 12 minutes late. If he walks at 6 km/h, he reaches 3 minutes early. Find the distance.
A. 4.0 km
B. 4.5 km
C. 5.5 km
D. 5.0 km
Answer: Option B
Solution (By JKSSB Mock Tests)
Time difference = 12 - (-3) = 15 minutes = 15/60 = 0.25 hours. Let distance be d. d / 4.5 - d / 6 = 0.25 => (4d - 3d) / 18 = 0.25 => d / 18 = 0.25 => d = 4.5 km.
Two trains 120 meters and 130 meters long are running in opposite directions at speeds of 45 km/h and 45 km/h respectively. In what time will they cross each other?
A commuter departs from outpost A at 5:00 AM at 25 km/h. Another starts from A at 7:00 AM at 35 km/h tracking along the same direction corridor. At what distance away from A will they intercept?
Explanation:
By 7:00 AM, the first commuter tracks for 2 hours, covering 25 * 2 = 50 km. Relative speed index = 35 - 25 = 10 km/h. Time to intercept = 50 / 10 = 5 hours. Distance path from point A = Speed of second commuter * Intercept Time = 35 * 5 = 175 km.
A commuter sets off from point M at 7 AM walking at 5 km/h. Another departs M at 9 AM in the same direction at 8 km/h. At what distance from M do they meet?
Explanation:
By 9 AM, the first commuter has walked for 2 hours, covering 5 * 2 = 10 km. Relative speed = 8 - 5 = 3 km/h. Time taken to meet = 10 / 3 hours. Distance from M = Speed of second commuter * Time = 8 * (10/3) = 80/3 = 26.66 km.
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