A private van tracks at 40 km/h for 4 hours and then steps up to 60 km/h for the next 2 hours. Find the mean average speed. MCQ with Answer and Explanation

A private van tracks at 40 km/h for 4 hours and then steps up to 60 km/h for the next 2 hours. Find the mean average speed.
A. 48.00 km/h
B. 46.66 km/h
C. 50.00 km/h
D. 45.33 km/h
Answer: Option B
Solution (By JKSSB Mock Tests)
Distance 1 = 40 * 4 = 160 km. Distance 2 = 60 * 2 = 120 km. Total distance = 280 km. Total time = 6 hours. Average speed = 280 / 6 = 46.66 km/h.

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Practice More Time Speed and Distance Questions

Question #1
A man covers half of his journey at 40 km/h and the remaining half at 60 km/h. What is his average speed?
A. 48 km/h
B. 54 km/h
C. 52 km/h
D. 50 km/h

Correct Answer: Option A


Explanation:
Average Speed = (2 * 40 * 60) / (40 + 60) = 4800 / 100 = 48 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
A train 100 meters long passes a static observer in 5 seconds. How long will it take to pass a platform 260 meters long?
A. 16 seconds
B. 20 seconds
C. 18 seconds
D. 22 seconds

Correct Answer: Option C


Explanation:
Speed of train = 100 / 5 = 20 m/s. Total distance to pass platform = 100 + 260 = 360 meters. Time taken = 360 / 20 = 18 seconds.

This question belongs to: Maths Time Speed and Distance
Question #3
In a 200-meter sprint, X beats Y by 20 meters and Y beats Z by 10 meters. By how many meters does X beat Z in the same race?
A. 30 meters
B. 28 meters
C. 29 meters
D. 32 meters

Correct Answer: Option C


Explanation:
When X covers 200m, Y covers 180m. When Y covers 200m, Z covers 190m. Thus, when Y covers 180m, Z covers 190 * (180 / 200) = 171m. Therefore, when X covers 200m, Z covers 171m. X beats Z by 200 - 171 = 29 meters.

This question belongs to: Maths Time Speed and Distance