A projectile is launched at 30° with speed 20 m/s. Horizontal range is: (g=10 m/s²)

Question

Team JKSSB Mock Tests · Accepted Answer

Range R = u²sin(2θ)/g = (20)²×sin(60°)/10 = 400×(√3/2)/10 = 20√3 m. Formula applies for level ground projection. Memory tip: sin(2θ) for θ=30° is sin60°=√3/2. Standard projectile calculation frequently appearing in competitive exams with trigonometric values.

A projectile is launched at 30° with speed 20 m/s. Horizontal range is: (g=10 m/s²) MCQ with Answer and Explanation

Solution (By JKSSB Mock Tests)

Discuss this Question (0)

Practice More Physics Questions