A reduction of 20% in the price of sugar enables a purchaser to obtain 4 kg more for Rs. 160. What is the original price per kg? MCQ with Answer and Explanation

A reduction of 20% in the price of sugar enables a purchaser to obtain 4 kg more for Rs. 160. What is the original price per kg?
A. Rs. 12
B. Rs. 10
C. Rs. 8
D. Rs. 15
Answer: Option B
Solution (By JKSSB Mock Tests)
20% of 160 = 32. This Rs. 32 buys 4 kg sugar. Reduced price = 32 / 4 = Rs. 8/kg. Let original price be x. 0.8x = 8. x = Rs. 10/kg.

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Practice More Profit And Loss Questions

Question #1
A trader mixes 26 kg of wheat at Rs. 20/kg with 30 kg of wheat at Rs. 36/kg and sells the mixture at Rs. 30/kg. What is his profit percentage?
A. 5.6%
B. 4%
C. 5%
D. 6.25%

Correct Answer: Option C


Explanation:
Total Cost Price = (26 * 20) + (30 * 36) = 520 + 1080 = 1600. Total quantity = 56 kg. Total Selling Price = 56 * 30 = 1680. Profit = 80. Profit percentage = (80 / 1600) * 100 = 5%.

This question belongs to: Maths Profit And Loss
Question #2
A reduction of 20% in the price of sugar enables a person to buy 5 kg more for Rs. 400. What is the original price per kg?
A. Rs. 16
B. Rs. 15
C. Rs. 20
D. Rs. 25

Correct Answer: Option C


Explanation:
Let original price = P. Reduced price = 0.8P. (400 / 0.8P) - (400 / P) = 5. (500 / P) - (400 / P) = 5. 100 / P = 5. P = 20.

This question belongs to: Maths Profit And Loss
Question #3
A trader marks his goods 20% above cost and gives a discount of 10%. What is his profit percent?
A. 15%
B. 10%
C. 8%
D. 12%

Correct Answer: Option C


Explanation:
CP=100, MP=120, SP=120*0.9=108, profit=8%.

This question belongs to: Maths Profit And Loss