A reduction of 20% in the price of sugar enables a purchaser to obtain 4 kg more for Rs. 160. What is the original price per kg? MCQ with Answer and Explanation

Question

A reduction of 20% in the price of sugar enables a purchaser to obtain 4 kg more for Rs. 160. What is the original price per kg?

A. Rs. 8

B. Rs. 10

C. Rs. 12

D. Rs. 15

Answer: Option B

Solution (By JKSSB Mock Tests)

20% of 160 = 32. This Rs. 32 buys 4 kg sugar. Reduced price = 32 / 4 = Rs. 8/kg. Let original price be x. 0.8x = 8. x = Rs. 10/kg.

This question belongs to: Maths Profit And Loss

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Question #1

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A trader marks his goods 30% above cost and gives a discount of 15%. What is his profit percent?

A. 10.5%

B. 12%

C. 15%

D. 9%

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Correct Answer: Option A

Explanation:
Let CP = 100. MP = 130. SP = 130 * 0.85 = 110.5. Profit = 10.5%.

This question belongs to: Maths Profit And Loss

Question #2

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A dealer sells a product for Rs. 920, losing 8%. Find the cost price.

A. Rs. 1020

B. Rs. 980

C. Rs. 950

D. Rs. 1000

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Correct Answer: Option D

Explanation:
SP = 92% of CP => CP = 920 / 0.92 = 1000.

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Question #3

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A person buys 80 kg of rice and sells it at a profit of as much money as he paid for 30 kg. His profit percentage is:

A. 35%

B. 30%

C. 37.5%

D. 27.5%

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Correct Answer: Option C

Explanation:
Let Cost Price of 1 kg = 1. Cost Price of 80 kg = 80. Profit = Cost Price of 30 kg = 30. Profit percentage = (30 / 80) * 100 = 37.5%.

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