A satellite is orbiting close to Earth's surface. Its orbital speed is (g = 10 m/s², R = 6400 km) MCQ with Answer and Explanation

A satellite is orbiting close to Earth's surface. Its orbital speed is (g = 10 m/s², R = 6400 km)
A. 16 km/s
B. 8 km/s
C. 4 km/s
D. 11.2 km/s
Answer: Option B
Solution (By JKSSB Mock Tests)
v = √(gR) = √(10×6400×10³) = √(64×10⁶) = 8×10³ m/s = 8 km/s. Escape velocity 11.2 km/s.

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Angular momentum dimensions:
A. [MLT⁻¹]
B. [ML²T⁻²]
C. [ML²T⁻¹]
D. [M⁰L⁰T⁰]

Correct Answer: Option C


Explanation:
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Question #2
Two forces 3 N and 4 N act at right angles. Resultant magnitude is:
A. 1 N
B. 5 N
C. 12 N
D. 7 N

Correct Answer: Option B


Explanation:
For perpendicular forces: R = √(F₁² + F₂²) = √(9 + 16) = √25 = 5 N. Pythagorean theorem applies for vector addition at 90°. Memory aid: '3-4-5 triangle for perpendicular forces'. Basic vector addition problem testing magnitude calculation, common in mechanics sections of competitive exams.

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Question #3
A body travels first half distance at speed v₁ and second half at v₂. Average speed is:
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C. √(v₁v₂)
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Correct Answer: Option B


Explanation:
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This question belongs to: Science Physics