A shopkeeper allows a 10% discount on the marked price of a camera. If the camera costs him Rs. 600, what should be the marked price to make a profit of 20%? MCQ with Answer and Explanation

A shopkeeper allows a 10% discount on the marked price of a camera. If the camera costs him Rs. 600, what should be the marked price to make a profit of 20%?
A. Rs. 900
B. Rs. 750
C. Rs. 850
D. Rs. 800
Answer: Option D
Solution (By JKSSB Mock Tests)
Cost Price = 600. Target Selling Price for 20% profit = 600 * 1.20 = 720. Marked Price * 0.90 = 720. Marked Price = 720 / 0.90 = 800.

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Practice More Profit And Loss Questions

Question #1
A man buys 100 oranges for Rs. 400. 20 oranges are rotten and thrown away. At what rate per dozen should he sell the remaining oranges to gain 20% on the whole transaction?
A. Rs. 60
B. Rs. 72
C. Rs. 64
D. Rs. 80

Correct Answer: Option B


Explanation:
Total Cost Price = 400. Desired Total Selling Price = 400 * 1.20 = 480. Remaining oranges = 80. Selling Price per orange = 480 / 80 = 6. Selling Price per dozen = 6 * 12 = 72.

This question belongs to: Maths Profit And Loss
Question #2
A trader mixes two varieties of tea costing Rs. 50/kg and Rs. 60/kg in the ratio 2:3. He sells the mixture at Rs. 67.20/kg. Find his profit percentage.
A. 25%
B. 15%
C. 18%
D. 20%

Correct Answer: Option D


Explanation:
Cost of 5 kg mixture = (2 * 50) + (3 * 60) = 100 + 180 = 280. Cost per kg = 280 / 5 = 56. Selling Price = 67.20. Profit = 11.20. Profit percentage = (11.20 / 56) * 100 = 20%.

This question belongs to: Maths Profit And Loss
Question #3
A shopkeeper sells a chair for Rs. 800, gaining 25%. Find the cost price.
A. Rs. 680
B. Rs. 640
C. Rs. 660
D. Rs. 620

Correct Answer: Option B


Explanation:
CP = 800/1.25 = 640.

This question belongs to: Maths Profit And Loss