A shopkeeper sells a fan for Rs. 1080, losing 10%. Find the cost price. MCQ with Answer and Explanation

Question
A shopkeeper sells a fan for Rs. 1080, losing 10%. Find the cost price.
A. Rs. 1150
B. Rs. 1200
C. Rs. 1100
D. Rs. 1250
Answer: Option B
Solution (By JKSSB Mock Tests)
SP = 90% of CP => CP = 1080 / 0.9 = 1200.
This question belongs to: Maths Profit And Loss
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Question #1
A man buys 100 oranges for Rs. 400. 20 oranges are rotten and thrown away. At what rate per dozen should he sell the remaining oranges to gain 20% on the whole transaction?
A. Rs. 72
B. Rs. 64
C. Rs. 60
D. Rs. 80
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Correct Answer: Option A

Explanation:
Total Cost Price = 400. Desired Total Selling Price = 400 * 1.20 = 480. Remaining oranges = 80. Selling Price per orange = 480 / 80 = 6. Selling Price per dozen = 6 * 12 = 72.
This question belongs to: Maths Profit And Loss
Question #2
A shopkeeper sells a bag for Rs. 480, losing 20%. Find the cost price.
A. Rs. 560
B. Rs. 600
C. Rs. 620
D. Rs. 580
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Correct Answer: Option B

Explanation:
SP = 80% of CP => CP = 480 / 0.8 = 600.
This question belongs to: Maths Profit And Loss
Question #3
A man buys oranges at 5 for Rs. 10 and an equal number at 4 for Rs. 10. He mixes them and sells the mixture at 9 for Rs. 20. Find his profit or loss percentage.
A. Loss of 2.5%
B. No profit no loss
C. Loss of 1.23%
D. Profit of 1.23%
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Correct Answer: Option C

Explanation:
Buy 20 oranges of type 1 for Rs. 40. Buy 20 oranges of type 2 for Rs. 50. Total 40 oranges cost Rs. 90. Cost Price of 1 orange = 90 / 40 = 2.25. Selling Price of 9 oranges = 20. Selling Price of 1 orange = 20 / 9 = 2.222. Loss = 2.25 - 2.222 = 0.0277. Loss percentage = (0.0277 / 2.25) * 100 = 1.23% loss.
This question belongs to: Maths Profit And Loss
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