A student walking at 3 km/h reaches his school 15 minutes late. If he walks at 4 km/h, he reaches 15 minutes early. Find the distance. MCQ with Answer and Explanation

A student walking at 3 km/h reaches his school 15 minutes late. If he walks at 4 km/h, he reaches 15 minutes early. Find the distance.
A. 8 km
B. 6 km
C. 4 km
D. 5 km
Answer: Option B
Solution (By JKSSB Mock Tests)
Time difference = 15 - (-15) = 30 minutes = 0.5 hours. Let distance be d. d/3 - d/4 = 0.5 => d/12 = 0.5 => d = 6 km.

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Practice More Time Speed and Distance Questions

Question #1
Excluding stoppages, a transit bus maintains an average speed of 75 km/h, and including stoppages its speed is 60 km/h. Find the stoppage time per hour.
A. 15 minutes
B. 12 minutes
C. 18 minutes
D. 10 minutes

Correct Answer: Option A


Explanation:
Stoppage time per hour = (Fast speed - Slow speed) / Fast speed = (75 - 60) / 75 = 15 / 75 = 1/5 hour. Converting to minutes = (1/5) * 60 = 15 minutes.

This question belongs to: Maths Time Speed and Distance
Question #2
The speed of two cyclists are in the ratio 4 : 7. If they cover the same total distance, what is the ratio of the time taken by them?
A. 4 : 7
B. 16 : 49
C. 49 : 16
D. 7 : 4

Correct Answer: Option D


Explanation:
Since time is inversely proportional to speed when distance is constant, the ratio of time taken is the reciprocal of the speed ratio: 1/4 : 1/7 = 7 : 4.

This question belongs to: Maths Time Speed and Distance
Question #3
A train 100 meters long passes a static observer in 5 seconds. How long will it take to pass a platform 260 meters long?
A. 16 seconds
B. 20 seconds
C. 22 seconds
D. 18 seconds

Correct Answer: Option D


Explanation:
Speed of train = 100 / 5 = 20 m/s. Total distance to pass platform = 100 + 260 = 360 meters. Time taken = 360 / 20 = 18 seconds.

This question belongs to: Maths Time Speed and Distance