A thief is spotted by a policeman from a distance of 200 meters. The thief runs at 10 km/h and the policeman chases him at 12 km/h. Find the distance covered by the thief before he is caught. MCQ with Answer and Explanation
A thief is spotted by a policeman from a distance of 200 meters. The thief runs at 10 km/h and the policeman chases him at 12 km/h. Find the distance covered by the thief before he is caught.
A. 900 meters
B. 1200 meters
C. 1000 meters
D. 1100 meters
Answer: Option C
Solution (By JKSSB Mock Tests)
Relative speed = 12 - 10 = 2 km/h. Time to catch the thief = 0.2 km / 2 km/h = 0.1 hours. Distance covered by thief = Speed * Time = 10 km/h * 0.1 hours = 1 km = 1000 meters.
Explanation:
New speed = 7/9 of usual speed => New time = 9/7 of usual time. Difference = 2/7 of usual time = 20 minutes. Therefore, 1/7 of usual time = 10 minutes => Usual time = 70 minutes.
The speeds of two cars are in the ratio 4 : 3. If they cover the same distance, and the slower car takes 2 hours, how much time does the faster car take?
Explanation:
Ratio of speeds = 4:3, so ratio of times taken = 3:4. The slower car corresponds to 4 parts = 2 hours => 1 part = 0.5 hours. Time for the faster car = 3 parts = 3 * 0.5 = 1.5 hours.
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