The speeds of two cars are in the ratio 4 : 3. If they cover the same distance, and the slower car takes 2 hours, how much time does the faster car take? MCQ with Answer and Explanation
The speeds of two cars are in the ratio 4 : 3. If they cover the same distance, and the slower car takes 2 hours, how much time does the faster car take?
A. 1.8 hours
B. 1.5 hours
C. 1.6 hours
D. 1.2 hours
Answer: Option B
Solution (By JKSSB Mock Tests)
Ratio of speeds = 4:3, so ratio of times taken = 3:4. The slower car corresponds to 4 parts = 2 hours => 1 part = 0.5 hours. Time for the faster car = 3 parts = 3 * 0.5 = 1.5 hours.
A car covers a distance from town X to town Y at a speed of 45 km/h and returns at a speed of 75 km/h. If the total journey takes 8 hours, find the one-way distance between the two towns.
Explanation:
Let the one-way distance be d km. Time taken forward = d/45 and return = d/75. Given: d/45 + d/75 = 8. (5d + 3d) / 225 = 8 => 8d / 225 = 8 => d = 225 km.
A car driver leaves Bangalore at 8:30 AM and expects to reach a place 300 km away at 12:30 PM. At 10:30 AM he finds that he has covered only 40% of the distance. By how much must he increase the speed of the car to reach on scheduled time?
Explanation:
Total time available = 4 hours. At 10:30 AM (after 2 hours), distance covered = 40% of 300 = 120 km. Remaining distance = 180 km. Remaining time = 12:30 PM - 10:30 AM = 2 hours. Required speed = 180 / 2 = 90 km/h. Original speed = 120 / 2 = 60 km/h. Increase in speed = 90 - 60 = 30 km/h.
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