A train 200 meters long passes a running man in 10 seconds when both move in the same direction. If the speed of the man is 6 km/h, find the speed of the train. MCQ with Answer and Explanation
A train 200 meters long passes a running man in 10 seconds when both move in the same direction. If the speed of the man is 6 km/h, find the speed of the train.
A. 72 km/h
B. 78 km/h
C. 90 km/h
D. 84 km/h
Answer: Option B
Solution (By JKSSB Mock Tests)
Relative speed = 200 / 10 = 20 m/s = 20 * (18/5) = 72 km/h. In the same direction, Relative Speed = Speed of train - Speed of man => 72 = Speed of train - 6 => Speed of train = 78 km/h.
The speeds of two cars are in the ratio 4 : 3. If they cover the same distance, and the slower car takes 2 hours, how much time does the faster car take?
Explanation:
Ratio of speeds = 4:3, so ratio of times taken = 3:4. The slower car corresponds to 4 parts = 2 hours => 1 part = 0.5 hours. Time for the faster car = 3 parts = 3 * 0.5 = 1.5 hours.
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