A train 300 meters long requires exactly 25 seconds to pass a railway worker running at 6 km/h in the opposite direction. Find the speed of the train. MCQ with Answer and Explanation

A train 300 meters long requires exactly 25 seconds to pass a railway worker running at 6 km/h in the opposite direction. Find the speed of the train.
A. 40.0 km/h
B. 34.2 km/h
C. 37.2 km/h
D. 43.2 km/h
Answer: Option C
Solution (By JKSSB Mock Tests)
Relative speed = 300 / 25 = 12 m/s = 12 * (18/5) = 43.2 km/h. Since they move in opposite directions, Relative Speed = Speed of train + Speed of worker => 43.2 = Speed of train + 6 => Speed of train = 37.2 km/h.

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Practice More Time Speed and Distance Questions

Question #1
An athlete loops a regular hexagonal field of side 50 meters. If his speed is 15 km/h, find the time taken to complete one full lap.
A. 80 seconds
B. 64 seconds
C. 90 seconds
D. 72 seconds

Correct Answer: Option D


Explanation:
Perimeter of the hexagonal field = 6 * 50 = 300 meters. Speed = 15 km/h = 15 * (5/18) = 25/6 m/s. Time = Distance / Speed = 300 / (25/6) = 300 * 6 / 25 = 12 * 6 = 72 seconds.

This question belongs to: Maths Time Speed and Distance
Question #2
A luxury car handles a tracking route sector of 240 km. It finishes the first half segment stretch at 40 km/h and the second half sector at 60 km/h. Find the mean average speed recorded across the full route.
A. 50 km/h
B. 48 km/h
C. 46 km/h
D. 52 km/h

Correct Answer: Option B


Explanation:
Average Speed across sectors = 2xy / (x + y) = (2 * 40 * 60) / (40 + 60) = 4800 / 100 = 48 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3
A train starts from Delhi at 6:00 AM and reaches Ambala at 10:00 AM. Another train starts from Ambala at 8:00 AM and reaches Delhi at 11:30 AM. At what time do the two trains cross each other?
A. 9:12 AM
B. 8:56 AM
C. 9:36 AM
D. 9:24 AM

Correct Answer: Option B


Explanation:
Train 1 takes 4 hours, Train 2 takes 3.5 hours (7/2 hours). Let distance be LCM(4, 3.5) = 28 units. Speed of Train 1 = 7 units/h, Speed of Train 2 = 8 units/h. By 8:00 AM, Train 1 travels 2 hours * 7 = 14 units. Remaining distance = 28 - 14 = 14 units. Relative speed = 7 + 8 = 15 units/h. Time to meet after 8 AM = 14/15 hours = 56 minutes. Meeting time = 8:56 AM.

This question belongs to: Maths Time Speed and Distance