A transformer has 50 turns in the primary coil and 1000 turns in the secondary coil. If the primary voltage is 220V, what is the secondary voltage? MCQ with Answer and Explanation
A transformer has 50 turns in the primary coil and 1000 turns in the secondary coil. If the primary voltage is 220V, what is the secondary voltage?
A. 4400 V
B. 22000 V
C. 11 V
D. 440 V
Answer: Option A
Solution (By JKSSB Mock Tests)
The transformer equation relates voltages to the number of turns: V_secondary / V_primary = N_secondary / N_primary. We have N_p = 50, N_s = 1000, and V_p = 220V. Substituting the values gives V_s / 220 = 1000 / 50. V_s = 220 * 20 = 4400 Volts. This is a step-up transformer, increasing the voltage strictly by a factor of 20.
Explanation:
Work done is given by W = F * d * cos(theta). In uniform circular motion, the centripetal force is always directed strictly towards the center of the circle, while the instantaneous displacement (velocity vector) is tangential to the circle. The angle (theta) between them is exactly 90 degrees. Since cos(90) = 0, the work done by the centripetal force is always zero.
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