According to Joule's law of heating, the heat produced in a resistor is directly proportional to the square of: MCQ with Answer and Explanation

According to Joule's law of heating, the heat produced in a resistor is directly proportional to the square of:
A. Voltage
B. Time
C. Electric Current
D. Resistance
Answer: Option C
Solution (By JKSSB Mock Tests)
Joule's Law of Heating states that the heat (H) produced in a resistor is given by H = I²Rt. This indicates that the heat produced is directly proportional to the square of the electric current (I), directly proportional to the resistance (R), and directly proportional to the time (t) the current flows.

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Practice More Physics Questions

Question #1
The power factor in an AC circuit is defined as:
A. Both (a) and (c)
B. Ratio of resistance to impedance
C. Ratio of apparent power to true power
D. Cosine of phase angle between voltage and current

Correct Answer: Option A


Explanation:
Power factor = cosφ, where φ is phase angle between voltage and current. Also, power factor = R/Z (resistance/impedance) for series circuits, and = true power (W) / apparent power (VA). Thus both (a) and (c) are correct definitions. Memory tip: 'Power factor = cosφ = R/Z = P/S; ideal = 1 (purely resistive)'. This definition question tests AC circuit knowledge, crucial for competitive exams. Always link power factor to energy efficiency: low power factor means more current for same power, increasing losses.

This question belongs to: Science Physics
Question #2
Temperature where Fahrenheit reading is double Celsius reading:
A. 160°C
B. 40°C
C. 320°C
D. 80°C

Correct Answer: Option A


Explanation:
F = (9/5)C + 32. Given F = 2C: 2C = 1.8C + 32 ⇒ 0.2C = 32 ⇒ C = 160°. Verify: F = 2×160 = 320°; formula: (9/5)×160+32 = 288+32 = 320°. Memory aid: Solve linear equation for temperature conversion problems. Algebraic manipulation of scale relations frequently tested in competitive exams.

This question belongs to: Science Physics
Question #3
If the percentage error in measurement of radius of a sphere is 2%, the percentage error in volume is
A. 8%
B. 6%
C. 4%
D. 2%

Correct Answer: Option B


Explanation:
Volume V = (4/3)πr³, so ΔV/V = 3 Δr/r. Percentage error in volume = 3 × 2% = 6%.

This question belongs to: Science Physics