Explanation:
New speed = 7/9 of usual speed => New time = 9/7 of usual time. Difference = 2/7 of usual time = 12 minutes. 1/7 of usual time = 6 minutes => Usual time = 42 minutes.
A man can walk a distance in 4 hours and ride back in 3 hours. If he walks both ways, he takes 8 hours. How much time will he take if he rides both ways?
Explanation:
Let walking time one way be W and riding time one way be R. W + R = 7 hours. Walking both ways: 2W = 8 => W = 4 hours. Substituting W in first equation: 4 + R = 7 => R = 3 hours. Riding both ways: 2R = 2 * 3 = 6 hours.
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