If a stone dropped from the top of a tower reaches the ground in 4 seconds, what is the approximate height of the tower? (Take g = 10 m/s²) MCQ with Answer and Explanation
If a stone dropped from the top of a tower reaches the ground in 4 seconds, what is the approximate height of the tower? (Take g = 10 m/s²)
A. 60 m
B. 80 m
C. 40 m
D. 160 m
Answer: Option B
Solution (By JKSSB Mock Tests)
Using the second equation of motion for free fall: h = ut + ½gt². Since it is dropped, initial velocity (u) = 0. Time (t) = 4s, g = 10 m/s². The height h = 0 + ½(10)(4)² = 5 × 16 = 80 meters.
Explanation:
Biot-Savart law: field forms concentric circles around wire, direction by right-hand thumb rule. Magnitude B = μ₀I/(2πr), decreasing with distance. Memory tip: 'Right-hand rule: thumb = current, fingers = field circles'. Fundamental magnetism concept frequently tested in competitive exams.
Explanation:
Sir C. V. Raman discovered the Raman effect in 1928: inelastic scattering of photons by molecules, changing wavelength, providing information about molecular structure. He received the Nobel Prize in Physics in 1930. Photoelectric effect: Einstein; relativity: Einstein; electromagnetic induction: Faraday. Memory tip: 'Raman = scattering of light'. This scientist-discovery question tests knowledge of Indian contributions to physics, commonly featured in competitive exams. Always link Nobel laureates to their specific awarded work.
No comments yet. Be the first to start the discussion!