If momentum of a body increases by 100%, kinetic energy increases by MCQ with Answer and Explanation

If momentum of a body increases by 100%, kinetic energy increases by
A. 300%
B. 100%
C. 200%
D. 400%
Answer: Option A
Solution (By JKSSB Mock Tests)
KE = p²/2m. If p → 2p, KE' = 4KE, increase = 3KE = 300%. Frequently asked.

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Practice More Physics Questions

Question #1
A 6 V battery is connected to a 3 Ω resistor. Current is
A. 2 A
B. 0.5 A
C. 3 A
D. 18 A

Correct Answer: Option A


Explanation:
I = V/R = 6/3 = 2 A.

This question belongs to: Science Physics
Question #2
When a body falls freely under gravity, which statement is correct?
A. Kinetic energy decreases
B. Total energy is not conserved
C. Mechanical energy remains constant
D. Potential energy increases

Correct Answer: Option C


Explanation:
In free fall under gravity alone, mechanical energy (kinetic + potential) is conserved, assuming no air resistance. Potential energy decreases while kinetic energy increases, sum constant. Law of conservation of mechanical energy. Non-conservative forces absent.

This question belongs to: Science Physics
Question #3
If the momentum of a body is increased by 100%, its kinetic energy increases by
A. 300%
B. 400%
C. 100%
D. 200%

Correct Answer: Option A


Explanation:
Kinetic energy K = p²/(2m). If p becomes 2p (100% increase), K' = (2p)²/(2m) = 4p²/(2m) = 4K. So increase = 4K - K = 3K, i.e., 300% increase. Common mistake: think linear. Remember quadratic relationship. Percent increase = (new-old)/old × 100% = (4K-K)/K ×100 = 300%.

This question belongs to: Science Physics