In a 300-meter dash race, X completes the track in 33 seconds and Y completes it in 36 seconds. By what distance does X beat Y? MCQ with Answer and Explanation

In a 300-meter dash race, X completes the track in 33 seconds and Y completes it in 36 seconds. By what distance does X beat Y?
A. 22 meters
B. 25 meters
C. 30 meters
D. 28 meters
Answer: Option B
Solution (By JKSSB Mock Tests)
Speed of Y = 300 / 36 = 25/3 m/s. Distance covered by Y when X crosses the finish line at 33 seconds = (25/3) * 33 = 25 * 11 = 275 meters. Winning margin = 300 - 275 = 25 meters.

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Practice More Time Speed and Distance Questions

Question #1
A car covers a distance of 200 km at a uniform speed. If the speed is increased by 10 km/h, the journey takes 4 hours. Find the initial speed of the car.
A. 40 km/h
B. 35 km/h
C. 45 km/h
D. 50 km/h

Correct Answer: Option A


Explanation:
New speed = 200 / 4 = 50 km/h. Since the new speed is 10 km/h faster than the original speed, original speed = 50 - 10 = 40 km/h.

This question belongs to: Maths Time Speed and Distance
Question #2
A car travels a distance of 420 km at a certain speed. If the speed is increased by 15 km/h, it takes 5 hours for the journey. Find the original speed.
A. 65 km/h
B. 72 km/h
C. 69 km/h
D. 75 km/h

Correct Answer: Option C


Explanation:
New speed = 420 / 5 = 84 km/h. Since new speed is original speed + 15 km/h, the original speed = 84 - 15 = 69 km/h.

This question belongs to: Maths Time Speed and Distance
Question #3
Walking at 5/7 of his usual speed, a man reaches his destination 24 minutes late. What is his usual time?
A. 60 minutes
B. 70 minutes
C. 80 minutes
D. 50 minutes

Correct Answer: Option A


Explanation:
New speed = 5/7 of usual speed => New time = 7/5 of usual time. Difference = 2/5 of usual time = 24 minutes. 1/5 of usual time = 12 minutes => Usual time = 60 minutes.

This question belongs to: Maths Time Speed and Distance