Lens power P = -4 D. Focal length and type: MCQ with Answer and Explanation

Lens power P = -4 D. Focal length and type:
A. 25 cm, concave
B. 40 cm, concave
C. 25 cm, convex
D. 40 cm, convex
Answer: Option A
Solution (By JKSSB Mock Tests)
P = 1/f(m) ⇒ f = 1/P = 1/(-4) = -0.25 m = -25 cm. Negative focal length indicates diverging (concave) lens. Memory aid: 'Negative power = concave lens; f(cm) = 100/P(D)'. Direct lens power application frequently tested in competitive exams with sign convention awareness.

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