Time Speed and Distance MCQs

Maths

Time Speed and Distance MCQs

Practice Time, Speed and Distance MCQs with answers and detailed solutions. Learn train problems, boats and streams, relative speed, average speed, races, journeys and advanced quantitative aptitude questions for competitive examinations.

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Question #161
A man can walk a distance in 4 hours and ride back in 3 hours. If he walks both ways, he takes 8 hours. How much time will he take if he rides both ways?
A. 8 hours
B. 5 hours
C. 6 hours
D. 7 hours

Correct Answer: Option C


Explanation:
Let walking time one way be W and riding time one way be R. W + R = 7 hours. Walking both ways: 2W = 8 => W = 4 hours. Substituting W in first equation: 4 + R = 7 => R = 3 hours. Riding both ways: 2R = 2 * 3 = 6 hours.

This question belongs to: Maths Time Speed and Distance
Question #162
A car covers a distance of 450 km at a certain speed. If the speed is increased by 5 km/h, it takes 1 hour less to cover the same distance. Find the original speed of the car.
A. 55 km/h
B. 50 km/h
C. 40 km/h
D. 45 km/h

Correct Answer: Option D


Explanation:
Let original speed be s. 450/s - 450/(s+5) = 1 => 450(s + 5 - s) = s(s + 5) => 2250 = s(s + 5). Solving s^2 + 5s - 2250 = 0 gives (s - 45)(s + 50) = 0. Since speed is positive, s = 45 km/h.

This question belongs to: Maths Time Speed and Distance
Question #163
A train running at 36 km/h takes 12 seconds to cross a platform. Next, it takes 6 seconds to pass a telegraph post. Find the length of the platform.
A. 80 meters
B. 50 meters
C. 60 meters
D. 70 meters

Correct Answer: Option C


Explanation:
Speed of train = 36 * (5/18) = 10 m/s. Length of train = Speed * Time to cross post = 10 * 6 = 60 meters. Total distance to cross platform = Speed * Time = 10 * 12 = 120 meters. Platform length = 120 - 60 = 60 meters.

This question belongs to: Maths Time Speed and Distance
Question #164
A runner covers a 100-meter race. The winner finishes in 10 seconds while the runner-up finishes in 10.5 seconds. By what distance does the winner beat the runner-up?
A. 5.25 meters
B. 4.54 meters
C. 5.00 meters
D. 4.76 meters

Correct Answer: Option D


Explanation:
Speed of the runner-up = 100 / 10.5 = 200 / 21 m/s. Distance covered by the runner-up in 10 seconds = (200 / 21) * 10 = 2000 / 21 = 95.24 meters. Distance winner beats runner-up by = 100 - 95.24 = 4.76 meters.

This question belongs to: Maths Time Speed and Distance
Question #165
If a man walks at 12 km/h instead of 9 km/h, he travels 15 km more in the same time. Find the actual distance traveled by him.
A. 60 km
B. 35 km
C. 50 km
D. 45 km

Correct Answer: Option D


Explanation:
Let the time duration be t hours. Difference in distance = 12t - 9t = 3t = 15 km => t = 5 hours. Actual distance traveled = 9 * 5 = 45 km.

This question belongs to: Maths Time Speed and Distance
Question #166
A train 220 meters long passes a signal post in 11 seconds. How long will it take to cross a platform 300 meters long?
A. 26 seconds
B. 30 seconds
C. 24 seconds
D. 28 seconds

Correct Answer: Option A


Explanation:
Speed of train = 220 / 11 = 20 m/s. Total distance to cross platform = 220 + 300 = 520 meters. Time taken = 520 / 20 = 26 seconds.

This question belongs to: Maths Time Speed and Distance
Question #167
A motorboat covers a certain distance downstream in a river in 3 hours and returns upstream in 4 hours. If the speed of the river current is 3 km/h, find the speed of the motorboat in still water.
A. 18 km/h
B. 24 km/h
C. 21 km/h
D. 27 km/h

Correct Answer: Option C


Explanation:
Let speed of boat in still water be v. Downstream speed = v + 3, Upstream speed = v - 3. Distance is same, so 3(v + 3) = 4(v - 3) => 3v + 9 = 4v - 12 => v = 21 km/h.

This question belongs to: Maths Time Speed and Distance
Question #168
A cyclist travels at a speed of 12 km/h for the first 10 km and at a speed of 10 km/h for the next 12 km. Find his average speed for the entire trip.
A. 10.45 km/h
B. 11.24 km/h
C. 11.00 km/h
D. 10.83 km/h

Correct Answer: Option D


Explanation:
Total distance = 10 + 12 = 22 km. Total time taken = 10/12 + 12/10 = 5/6 + 6/5 = (25 + 36) / 30 = 61 / 30 hours. Average speed = 22 / (61/30) = 660 / 61 = 10.82 hours (approx 10.83 km/h).

This question belongs to: Maths Time Speed and Distance
Question #169
A train 130 meters long passes a bridge of length 270 meters in 30 seconds. Find the speed of the train in km/h.
A. 45 km/h
B. 54 km/h
C. 50 km/h
D. 48 km/h

Correct Answer: Option D


Explanation:
Total distance = 130 + 270 = 400 meters. Speed = 400 / 30 = 40/3 m/s. In km/h = (40/3) * (18/5) = 8 * 6 = 48 km/h.

This question belongs to: Maths Time Speed and Distance
Question #170
A person runs a distance of 1200 meters along a straight road in 4 minutes. What is his speed in km/h?
A. 20 km/h
B. 24 km/h
C. 18 km/h
D. 15 km/h

Correct Answer: Option C


Explanation:
Time = 4 minutes = 240 seconds. Speed = 1200 / 240 = 5 m/s. Speed in km/h = 5 * (18/5) = 18 km/h.

This question belongs to: Maths Time Speed and Distance
Question #171
A man rows 24 km downstream in 2 hours and the same distance upstream in 6 hours. Find the speed of the stream.
A. 4 km/h
B. 5 km/h
C. 6 km/h
D. 3 km/h

Correct Answer: Option A


Explanation:
Downstream speed = 24 / 2 = 12 km/h. Upstream speed = 24 / 6 = 4 km/h. Speed of stream = (12 - 4) / 2 = 8 / 2 = 4 km/h.

This question belongs to: Maths Time Speed and Distance
Question #172
A car covers a distance of 360 km at a uniform speed. If the speed had been 15 km/h more, it would have taken 2 hours less for the journey. Find the original speed of the car.
A. 55 km/h
B. 45 km/h
C. 50 km/h
D. 60 km/h

Correct Answer: Option B


Explanation:
Let original speed be s. 360/s - 360/(s+15) = 2 => 180/s - 180/(s+15) = 1 => 180(15) = s(s+15) => 2700 = s(s+15). Solving s^2 + 15s - 2700 = 0 gives (s - 45)(s + 60) = 0. Since speed is positive, s = 45 km/h.

This question belongs to: Maths Time Speed and Distance
Question #173
A wheel of diameter 70 cm makes 400 revolutions per minute. Find the speed of the vehicle in km/h.
A. 60.0 km/h
B. 48.2 km/h
C. 52.8 km/h
D. 55.4 km/h

Correct Answer: Option C


Explanation:
Radius r = 35 cm = 0.35 meters. Circumference = 2 * (22/7) * 0.35 = 2.2 meters. Distance covered in 1 minute = 400 * 2.2 = 880 meters. Distance covered in 1 hour = 880 * 60 = 52800 meters = 52.8 km. Speed = 52.8 km/h.

This question belongs to: Maths Time Speed and Distance
Question #174
A man leaves point A at 6 AM at a speed of 4 km/h. Another man leaves point A from the same direction at 8 AM at a speed of 6 km/h. At what distance from point A will they meet?
A. 24 km
B. 20 km
C. 32 km
D. 28 km

Correct Answer: Option A


Explanation:
By 8 AM, the first man has traveled for 2 hours, covering 4 * 2 = 8 km. Relative speed = 6 - 4 = 2 km/h. Time taken to meet = 8 / 2 = 4 hours. Distance from A = Speed of second man * Time = 6 * 4 = 24 km.

This question belongs to: Maths Time Speed and Distance
Question #175
Excluding stoppages, a truck travels at 90 km/h and including stoppages it travels at 75 km/h. How many minutes does the truck stop per hour?
A. 15 minutes
B. 12 minutes
C. 8 minutes
D. 10 minutes

Correct Answer: Option D


Explanation:
Stoppage time per hour = (90 - 75) / 90 = 15 / 90 = 1/6 hour. In minutes = (1/6) * 60 = 10 minutes.

This question belongs to: Maths Time Speed and Distance
Question #176
A train 250 meters long takes 30 seconds to cross a man running at 6 km/h in the opposite direction. Find the speed of the train.
A. 36 km/h
B. 42 km/h
C. 30 km/h
D. 24 km/h

Correct Answer: Option D


Explanation:
Relative speed = 250 / 30 = 25/3 m/s = (25/3) * (18/5) = 30 km/h. In opposite directions, Relative Speed = Speed of train + Speed of man => 30 = Speed of train + 6 => Speed of train = 24 km/h.

This question belongs to: Maths Time Speed and Distance
Question #177
A runner covers a circular path of radius 70 meters in 44 seconds. What is his speed in km/h?
A. 30 km/h
B. 36 km/h
C. 40 km/h
D. 45 km/h

Correct Answer: Option B


Explanation:
Circumference of circular path = 2 * (22/7) * 70 = 440 meters. Speed = 440 / 44 = 10 m/s. In km/h = 10 * (18/5) = 36 km/h.

This question belongs to: Maths Time Speed and Distance
Question #178
A person walks from his residence to his office at 4 km/h and arrives 15 minutes late. If he increases his speed to 6 km/h, he still arrives 5 minutes late. Find the distance.
A. 2 km
B. 2.5 km
C. 1.5 km
D. 3 km

Correct Answer: Option A


Explanation:
Time difference = 15 - 5 = 10 minutes = 10 / 60 = 1/6 hour. Let distance be d. d/4 - d/6 = 1/6 => d/12 = 1/6 => d = 2 km.

This question belongs to: Maths Time Speed and Distance
Question #179
A boatman rows 15 km downstream in 3 hours and 12 km upstream in 4 hours. What is the speed of the boat in still water?
A. 3.5 km/h
B. 4.5 km/h
C. 4 km/h
D. 5 km/h

Correct Answer: Option C


Explanation:
Downstream speed = 15 / 3 = 5 km/h. Upstream speed = 12 / 4 = 3 km/h. Speed in still water = (5 + 3) / 2 = 4 km/h.

This question belongs to: Maths Time Speed and Distance
Question #180
In a 100-meter race, A can beat B by 20 meters and B can beat C by 10 meters. By how many meters can A beat C in the same race?
A. 32 meters
B. 26 meters
C. 30 meters
D. 28 meters

Correct Answer: Option D


Explanation:
When A covers 100m, B covers 80m. When B covers 100m, C covers 90m. Thus, when B covers 80m, C covers 90 * (80 / 100) = 72m. Therefore, when A covers 100m, C covers 72m. A beats C by 100 - 72 = 28 meters.

This question belongs to: Maths Time Speed and Distance