Successive discounts of x% and 15% are equivalent to a single discount of 32%. What is the value of x? MCQ with Answer and Explanation

Successive discounts of x% and 15% are equivalent to a single discount of 32%. What is the value of x?
A. 20
B. 18
C. 15
D. 22
Answer: Option A
Solution (By JKSSB Mock Tests)
Equivalent multiplier = (1 - x/100) * 0.85. 1 - 0.32 = 0.68. (1 - x/100) * 0.85 = 0.68. 1 - x/100 = 0.68 / 0.85 = 0.80. x/100 = 0.20. x = 20.

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Practice More Profit And Loss Questions

Question #1
Ravi sold an article to Mohan at a profit of 10%. Mohan sold it to Shyam at a profit of 20%. If Shyam paid Rs. 1320, find the cost price for Ravi.
A. Rs. 1200
B. Rs. 1000
C. Rs. 1100
D. Rs. 900

Correct Answer: Option B


Explanation:
Let Ravi's Cost Price = X. X * 1.10 * 1.20 = 1320. 1.32X = 1320. X = 1000.

This question belongs to: Maths Profit And Loss
Question #2
A man bought two horses for Rs. 30000. He sold one at a loss of 15% and the other at a profit of 19%. If the selling price of both horses is the same, what is the cost price of the second horse?
A. Rs. 12500
B. Rs. 10000
C. Rs. 17500
D. Rs. 15000

Correct Answer: Option A


Explanation:
Let the cost prices be CP1 and CP2. CP1 + CP2 = 30000. Given 0.85 * CP1 = 1.19 * CP2, which simplifies to CP1 / CP2 = 119 / 85 = 7 / 5. The ratio is 7:5. Total parts = 12. 1 part = 30000 / 12 = 2500. CP2 = 5 parts = 5 * 2500 = Rs. 12500.

This question belongs to: Maths Profit And Loss
Question #3
A shopkeeper marks his goods 40% above cost and gives a discount of 10%. What is his profit percent?
A. 26%
B. 30%
C. 20%
D. 25%

Correct Answer: Option A


Explanation:
Let CP = 100, MP = 140, SP = 140*0.9 = 126, profit = 26%.

This question belongs to: Maths Profit And Loss