The de Broglie wavelength associated with a moving particle is inversely proportional to its: MCQ with Answer and Explanation

The de Broglie wavelength associated with a moving particle is inversely proportional to its:
A. Momentum
B. Velocity only
C. Mass only
D. Kinetic energy
Answer: Option A
Solution (By JKSSB Mock Tests)
Louis de Broglie proposed that matter exhibits wave-like properties. The de Broglie wavelength (lambda) of a particle is given by the formula lambda = h / p, where 'h' is Planck's constant and 'p' is the linear momentum (mass * velocity) of the particle. Therefore, the wavelength is strictly inversely proportional to the momentum of the moving particle.

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Practice More Physics Questions

Question #1
According to the law of conservation of energy, in an isolated system:
A. Kinetic energy remains constant
B. Potential energy remains constant
C. Total mechanical energy remains constant if only conservative forces act
D. Thermal energy is always zero

Correct Answer: Option C


Explanation:
Law of conservation of energy states total energy (all forms) is conserved in isolated systems. For mechanical energy (KE + PE) to be conserved, only conservative forces (like gravity, spring) must act; non-conservative forces (friction) convert mechanical energy to heat. Option C precisely states this condition. Options A and B are incorrect as KE and PE individually vary. Option D is false as thermal energy can exist. Memory tip: 'Mechanical energy conserved ⇔ no non-conservative work'. This nuanced understanding is critical for energy problems in competitive exams, where distractors often omit the conservative force condition.

This question belongs to: Science Physics
Question #2
The SI unit of electric charge is
A. Volt
B. Ohm
C. Coulomb
D. Ampere

Correct Answer: Option C


Explanation:
Coulomb (C) is SI unit of charge. Ampere is unit of current (C/s). Volt is potential difference, ohm is resistance. One coulomb is charge transported by 1 A current in 1 s.

This question belongs to: Science Physics
Question #3
A spring with k=200 N/m is compressed by 0.1 m. Potential energy stored is
A. 20 J
B. 2 J
C. 0.5 J
D. 1 J

Correct Answer: Option D


Explanation:
U = ½ k x² = ½×200×0.01 = 1 J.

This question belongs to: Science Physics