The de Broglie wavelength associated with a moving particle is inversely proportional to its:
A. Momentum
B. Mass only
C. Velocity only
D. Kinetic energy
Answer: Option A
Solution (By JKSSB Mock Tests)
Louis de Broglie proposed that matter exhibits wave-like properties. The de Broglie wavelength (lambda) of a particle is given by the formula lambda = h / p, where 'h' is Planck's constant and 'p' is the linear momentum (mass * velocity) of the particle. Therefore, the wavelength is strictly inversely proportional to the momentum of the moving particle.
Explanation:
Lactometer is a type of hydrometer used to check purity of milk by measuring specific gravity. Adulteration with water lowers density. It doesn't measure temperature or viscosity directly.
Explanation:
Heat for phase change Q = m·L_f, where L_f is latent heat of fusion. Thus Q = 2 kg × 336 kJ/kg = 672 kJ. This direct application tests calorimetry fundamentals. Memory aid: 'Latent heat: Q = mL; no temperature change during phase transition'. Competitive exams frequently test such calculations with standard values. Always ensure units match (kg and kJ/kg here); convert if necessary. This problem assesses basic formula application skills essential for thermodynamics sections.
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