The force between two charges in vacuum is F. If a medium of dielectric constant 4 is introduced, force becomes MCQ with Answer and Explanation

The force between two charges in vacuum is F. If a medium of dielectric constant 4 is introduced, force becomes
A. 4F
B. 2F
C. F/2
D. F/4
Answer: Option D
Solution (By JKSSB Mock Tests)
F_medium = F_vacuum / K.

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Practice More Physics Questions

Question #1
If the percentage error in measuring the radius of a sphere is 2%, what will be the percentage error in the calculation of its volume?
A. 2%
B. 4%
C. 8%
D. 6%

Correct Answer: Option D


Explanation:
The volume of a sphere is given by V = (4/3)πr³. The formula for relative error in volume is (ΔV/V) = 3 × (Δr/r). Since the percentage error in radius (Δr/r × 100) is 2%, the percentage error in volume will be 3 × 2% = 6%. Constants like 4/3 and π do not contribute to the error.

This question belongs to: Science Physics
Question #2
The phenomenon of splitting of white light into its constituent colours is called
A. Scattering
B. Dispersion
C. Polarisation
D. Refraction

Correct Answer: Option B


Explanation:
Dispersion happens because refractive index varies with wavelength. Prism, rainbow. Scattering is Tyndall effect (blue sky). Polarisation restricts vibrations.

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Question #3
The least count of a screw gauge is 0.001 cm. The reading of a measurement is 0.250 cm. How many significant figures does it have?
A. 3
B. 4
C. 2
D. 1

Correct Answer: Option A


Explanation:
Reading 0.250 cm has three significant figures (2,5, and trailing zero after decimal). Least count gives precision, trailing zero indicates measurement to 0.001 cm, so it's significant.

This question belongs to: Science Physics