The SI unit of luminous intensity is MCQ with Answer and Explanation

The SI unit of luminous intensity is
A. Lumen
B. Candela
C. Lux
D. Watt
Answer: Option B
Solution (By JKSSB Mock Tests)
Candela (cd) is one of the seven SI base units, measures luminous intensity. Lumen is luminous flux (lm = cd·sr). Lux is illuminance (lx = lm/m²). Watt is power.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Physics Questions

Question #1
Critical angle for glass (n=1.5) to air:
A. 42°
B. 30°
C. 90°
D. 60°

Correct Answer: Option A


Explanation:
sinθ_c = n₂/n₁ = 1/1.5 = 2/3 ⇒ θ_c = sin⁻¹(0.667) ≈ 42°. Total internal reflection condition. Memory tip: 'θ_c = sin⁻¹(1/n) for denser to air'. Optics calculation frequently tested in competitive exams with standard refractive indices.

This question belongs to: Science Physics
Question #2
The percentage error in the measurement of mass is 1% and speed is 2%. Error in kinetic energy is
A. 5%
B. 6%
C. 2%
D. 4%

Correct Answer: Option A


Explanation:
KE = ½mv², ΔKE/KE = Δm/m + 2 Δv/v = 1% + 4% = 5%.

This question belongs to: Science Physics
Question #3
A block of wood floats in water with 60% of its volume submerged. In a liquid of density 0.8 g/cm³, the fraction of volume submerged will be:
A. 75%
B. 80%
C. 60%
D. 48%

Correct Answer: Option A


Explanation:
From floatation: ρ_wood/ρ_water = fraction submerged in water = 0.6. Thus ρ_wood = 0.6 g/cm³ (since ρ_water = 1 g/cm³). In new liquid (ρ_l = 0.8 g/cm³), fraction submerged f = ρ_wood/ρ_l = 0.6/0.8 = 0.75 = 75%. This uses the principle that fraction submerged equals density ratio. Memory aid: 'f = ρ_object / ρ_fluid'. Such comparative buoyancy problems test application of Archimedes' principle across scenarios, common in competitive exams. Always maintain consistent units (g/cm³ here simplifies calculation).

This question belongs to: Science Physics