A theft is reported at 4:00 AM. The thief runs at 50 km/h. The police begin chasing at 4:30 AM at 60 km/h. Find the distance from the starting point where the thief is caught.
Explanation:
In 30 minutes (0.5 hours), the thief covers 50 * 0.5 = 25 km. Relative speed = 60 - 50 = 10 km/h. Time taken to catch = 25 / 10 = 2.5 hours. Distance covered by police = 60 km/h * 2.5 hours = 150 km.
A thief is spotted by a policeman from a distance of 200 meters. The thief runs at 10 km/h and the policeman chases him at 12 km/h. Find the distance covered by the thief before he is caught.
Explanation:
Relative speed = 12 - 10 = 2 km/h. Time to catch the thief = 0.2 km / 2 km/h = 0.1 hours. Distance covered by thief = Speed * Time = 10 km/h * 0.1 hours = 1 km = 1000 meters.
Two outposts M and N are 320 km apart. Train A leaves M for N at 40 km/h at 6:00 AM. Train B leaves N for M at 60 km/h at 8:00 AM. At what time will they cross?
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