A man rides a bicycle at 12 km/h from his house to his school and reaches 5 minutes late. Next day he increases his speed to 15 km/h and reaches 5 minutes early. Find the distance between his house and school.
Two cars A and B depart an intersection at the same time at right angles. A moves North at 36 km/h and B travels East at 48 km/h. Find the direct distance separating them after 30 minutes.
Explanation:
Time = 30 minutes = 0.5 hours. Distance covered by A = 36 * 0.5 = 18 km. Distance covered by B = 48 * 0.5 = 24 km. Direct distance = sqrt(18^2 + 24^2) = sqrt(324 + 576) = sqrt(900) = 30 km.
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