The velocity of sound is maximum in MCQ with Answer and Explanation

The velocity of sound is maximum in
A. Vacuum
B. Air
C. Water
D. Steel
Answer: Option D
Solution (By JKSSB Mock Tests)
Speed of sound: solids > liquids > gases. In steel ~5000 m/s, water ~1500 m/s, air ~340 m/s. Vacuum no propagation. Speed depends on density and elasticity.

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Practice More Physics Questions

Question #1
The phenomenon of diffraction is evidence for the:
A. Particle nature of light
B. Wave nature of light
C. Electromagnetic nature of light
D. Dual nature of light

Correct Answer: Option B


Explanation:
Diffraction (bending of waves around obstacles) is a characteristic wave phenomenon, explained by Huygens' principle and wave superposition. It demonstrates light's wave nature, as particles would travel in straight lines. Particle nature is shown by photoelectric effect; dual nature combines both. Memory aid: 'Diffraction/interference ⇒ wave nature; photoelectric effect ⇒ particle nature'. This conceptual question tests wave-particle duality fundamentals, frequently examined in competitive exams. Always link specific phenomena to the aspect of light they demonstrate; competitive exams often combine both aspects in advanced questions requiring nuanced understanding.

This question belongs to: Science Physics
Question #2
A stone is dropped from a tower. The distance covered by it in the last second of its fall is equal to the distance covered in the first three seconds. The height of the tower is approximately: (g = 10 m/s²)
A. 180 m
B. 80 m
C. 125 m
D. 200 m

Correct Answer: Option C


Explanation:
Distance in first 3 seconds: s₃ = ½gt² = ½×10×9 = 45 m. Let total time be n seconds. Distance in nth second: sₙ = u + g(2n-1)/2 = 0 + 5(2n-1) = 10n - 5. Given sₙ = 45 m ⇒ 10n - 5 = 45 ⇒ n = 5 s. Total height h = ½gn² = ½×10×25 = 125 m. This problem combines equation of motion with logical reasoning about time intervals. Exam tip: For free fall from rest, distance in nth second = 5(2n-1) meters when g=10 m/s². Such numerical problems test application skills in competitive exams.

This question belongs to: Science Physics
Question #3
A body of mass 2 kg is moving with velocity 5 m/s. Its kinetic energy is
A. 5 J
B. 25 J
C. 50 J
D. 10 J

Correct Answer: Option B


Explanation:
K.E. = ½ m v² = ½ × 2 × 5² = 1 × 25 = 25 J. Use formula correctly. If velocity doubled, KE quadrupled. Unit joule.

This question belongs to: Science Physics