Two electric bulbs rated 60W, 220V and 100W, 220V are connected strictly in series across a 220V supply. Which bulb will glow brighter? MCQ with Answer and Explanation
Two electric bulbs rated 60W, 220V and 100W, 220V are connected strictly in series across a 220V supply. Which bulb will glow brighter?
A. Neither will glow.
B. 60W bulb
C. Both will glow with equal brightness.
D. 100W bulb
Answer: Option B
Solution (By JKSSB Mock Tests)
Resistance of a bulb is R = V^2 / P. The 60W bulb has a higher resistance than the 100W bulb. When connected in series, the exact same current (I) flows through both. The power consumed (which determines brightness) is given by P = I^2R. Since the 60W bulb has higher resistance (R), it consumes more power and glows brighter.
Explanation:
Motor converts electrical to mechanical energy using force on a current-carrying conductor in magnetic field (F = BIL). Electromagnetic induction is for generator. Motor principle: A current-carrying coil experiences torque in magnetic field.
Explanation:
Louis de Broglie proposed that matter exhibits wave-like properties. The de Broglie wavelength (lambda) of a particle is given by the formula lambda = h / p, where 'h' is Planck's constant and 'p' is the linear momentum (mass * velocity) of the particle. Therefore, the wavelength is strictly inversely proportional to the momentum of the moving particle.
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