When a source of sound moves faster than the speed of sound itself in that medium, it creates a conical wave front known as a: MCQ with Answer and Explanation

When a source of sound moves faster than the speed of sound itself in that medium, it creates a conical wave front known as a:
A. Standing wave
B. Transverse wave
C. Beat frequency
D. Shock wave
Answer: Option D
Solution (By JKSSB Mock Tests)
When an object (like a jet plane) exceeds the speed of sound (Mach 1), it overtakes the sound waves it produces. These sound waves pile up behind the object, superimposing constructively to form an intense, cone-shaped pressure wave called a shock wave. When this high-pressure cone sweeps over an observer on the ground, they hear a loud 'sonic boom'.

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Practice More Physics Questions

Question #1
Dimensional formula [M⁰L⁰T⁰] represents:
A. Strain
B. All of these
C. Angle
D. Refractive index

Correct Answer: Option B


Explanation:
Dimensionless quantities: angle (radian = arc/radius), strain (ΔL/L), refractive index (ratio of speeds). All have [M⁰L⁰T⁰]. Memory aid: 'Ratios of same dimensions ⇒ dimensionless'. Dimensional analysis question frequently tested in competitive exams to identify dimensionless physical quantities.

This question belongs to: Science Physics
Question #2
The dimensional formula of Planck's constant is identical to that of:
A. Force
B. Linear momentum
C. Torque
D. Angular momentum

Correct Answer: Option D


Explanation:
Planck's constant (h) has dimensions [ML²T⁻¹]. Angular momentum (L = mvr) has dimensions [M][LT⁻¹][L] = [ML²T⁻¹], matching exactly. Linear momentum is [MLT⁻¹], force is [MLT⁻²], and torque is [ML²T⁻²]. This dimensional equivalence is fundamental in quantum mechanics, linking wave-particle duality. Memory tip: Both represent 'action' quantities with identical dimensional structure. This concept frequently appears in competitive exams testing dimensional analysis skills.

This question belongs to: Science Physics
Question #3
A stone is dropped from a tower. The distance covered by it in the last second of its fall is equal to the distance covered in the first three seconds. The height of the tower is approximately: (g = 10 m/s²)
A. 125 m
B. 200 m
C. 80 m
D. 180 m

Correct Answer: Option A


Explanation:
Distance in first 3 seconds: s₃ = ½gt² = ½×10×9 = 45 m. Let total time be n seconds. Distance in nth second: sₙ = u + g(2n-1)/2 = 0 + 5(2n-1) = 10n - 5. Given sₙ = 45 m ⇒ 10n - 5 = 45 ⇒ n = 5 s. Total height h = ½gn² = ½×10×25 = 125 m. This problem combines equation of motion with logical reasoning about time intervals. Exam tip: For free fall from rest, distance in nth second = 5(2n-1) meters when g=10 m/s². Such numerical problems test application skills in competitive exams.

This question belongs to: Science Physics