Which characteristic of a sound wave determines its pitch? MCQ with Answer and Explanation

Which characteristic of a sound wave determines its pitch?
A. Frequency
B. Amplitude
C. Velocity
D. Wavelength
Answer: Option A
Solution (By JKSSB Mock Tests)
The pitch of a sound is a subjective sensation that is determined primarily by the frequency of the sound wave. Higher frequency waves are perceived as high-pitched sounds (like a whistle), while lower frequency waves are perceived as low-pitched sounds (like a bass drum). Amplitude determines the loudness of the sound.

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Practice More Physics Questions

Question #1
The centre of mass of a two-particle system lies on the line joining them, closer to
A. Heavier particle
B. Lighter particle
C. Midpoint always
D. Depends on velocity

Correct Answer: Option A


Explanation:
r_cm = (m1 r1 + m2 r2)/(m1+m2). Closer to heavier mass.

This question belongs to: Science Physics
Question #2
Assertion (A): It is easier to pull a lawn roller than to push it. Reason (R): Pushing increases the apparent weight of the roller, thereby increasing the frictional force.
A. Both A and R are true and R is the correct explanation of A.
B. A is false but R is true.
C. Both A and R are true but R is NOT the correct explanation of A.
D. A is true but R is false.

Correct Answer: Option A


Explanation:
When you pull a roller at an upward angle, the vertical component of the applied force acts strictly upwards, reducing the normal reaction (N = mg - Fsin_theta) and thus reducing friction (muN). When you push it at a downward angle, the vertical component adds to the weight (N = mg + Fsin_theta), increasing the normal reaction and consequently increasing the rolling friction.

This question belongs to: Science Physics
Question #3
The phenomenon of total internal reflection is used in:
A. Optical fibers
B. Both (a) and (b)
C. Neither
D. Diamond cutting

Correct Answer: Option B


Explanation:
Total internal reflection (TIR) is exploited in optical fibers for light transmission with minimal loss (core-cladding interface). In diamonds, high refractive index (n≈2.4) gives small critical angle (~24°), so most light undergoes TIR, enhancing brilliance through multiple reflections. Memory aid: 'TIR applications: optical fibers (communication), diamonds (sparkle), prisms (binoculars)'. This application question tests optics uses, frequently appearing in competitive exams. Always link physical principles to technological applications; competitive exams emphasize practical relevance of theoretical concepts.

This question belongs to: Science Physics