Which of the following graphs represents a body at rest? MCQ with Answer and Explanation

Which of the following graphs represents a body at rest?
A. Displacement-time graph parallel to time axis
B. Velocity-time graph with zero slope
C. Displacement-time graph with constant positive slope
D. Velocity-time graph with positive slope
Answer: Option A
Solution (By JKSSB Mock Tests)
For a body at rest, displacement remains constant over time. The displacement-time graph is a horizontal line, parallel to time axis, indicating zero slope (velocity = 0). Option A indicates constant velocity. Option B (velocity-time zero slope) means constant velocity, not necessarily rest (could be constant non-zero velocity). Option D indicates acceleration. So C is correct.

Discuss this Question (0)

No comments yet. Be the first to start the discussion!

Practice More Physics Questions

Question #1
A train 100 m long crosses a pole in 5 seconds. Its speed in km/h is
A. 36 km/h
B. 72 km/h
C. 50 km/h
D. 20 km/h

Correct Answer: Option B


Explanation:
Speed = distance/time = 100 m / 5 s = 20 m/s. Convert to km/h: multiply by 18/5 => 20 × 18/5 = 72 km/h. Pole is a point, so train's own length is the distance crossed. Speed in km/h = m/s × (18/5). 20 × 18/5 = 72.

This question belongs to: Science Physics
Question #2
The phenomenon of splitting of spectral lines in magnetic field is called
A. Zeeman effect
B. Raman effect
C. Stark effect
D. Compton effect

Correct Answer: Option A


Explanation:
Zeeman effect: splitting due to magnetic field. Stark effect due to electric field.

This question belongs to: Science Physics
Question #3
If the length of a simple pendulum is quadrupled (increased by a factor of 4), what happens to its time period?
A. It is halved.
B. It doubles.
C. It remains unchanged.
D. It quadruples.

Correct Answer: Option B


Explanation:
The time period of a simple pendulum is given by T = 2π√(L/g), where L is the length of the string and g is acceleration due to gravity. The time period is directly proportional to the square root of the length (T ∝ √L). If L becomes 4L, the new time period T' = √4 = 2 times the original. It doubles.

This question belongs to: Science Physics