Work moving charge on equipotential surface: MCQ with Answer and Explanation

Work moving charge on equipotential surface:
A. Zero
B. Path dependent
C. qV
D. Infinite
Answer: Option A
Solution (By JKSSB Mock Tests)
Equipotential: ΔV = 0 ⇒ W = qΔV = 0. Electric field perpendicular to equipotentials. Memory aid: 'Equipotential: no work to move charge along it'. Electrostatics concept frequently tested in competitive exams.

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Question #1
The focal length of a spherical mirror is related to its radius of curvature R by:
A. f = R/2
B. f = R
C. f = R²
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Correct Answer: Option A


Explanation:
For spherical mirrors (concave or convex), focal length f = R/2, where R is radius of curvature. This holds under paraxial approximation (small angles). Derivation uses geometry of reflection and small-angle approximations. Memory tip: 'Mirror: f = R/2; Lens: 1/f = (n-1)(1/R₁ - 1/R₂)'. This fundamental relation is frequently tested in optics sections of competitive exams. Always note sign conventions: f negative for convex mirrors, positive for concave; R follows same sign as f.

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Which characteristic of a sound wave determines its pitch?
A. Frequency
B. Velocity
C. Wavelength
D. Amplitude

Correct Answer: Option A


Explanation:
The pitch of a sound is a subjective sensation that is determined primarily by the frequency of the sound wave. Higher frequency waves are perceived as high-pitched sounds (like a whistle), while lower frequency waves are perceived as low-pitched sounds (like a bass drum). Amplitude determines the loudness of the sound.

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Nuclear fission is the process in which
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Correct Answer: Option C


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