A can do a piece of work in 40 days. He works at it for 8 days and then B finishes it in 16 days. How long will A and B together take to complete the work?
Explanation:
Let total work be 40 units. Efficiency of A = 1 unit/day. In 8 days, A completes 8 units. Remaining work = 40 - 8 = 32 units. B finishes 32 units in 16 days, so B's efficiency = 32 / 16 = 2 units/day. Combined efficiency of A and B = 1 + 2 = 3 units/day. Time taken together = 40 / 3 = 13(1/3) days.
A can complete a piece of work in 12 days, and B can complete the same work in 24 days. If they work together, how many days will it take them to complete the work?
Explanation:
A's 1-day work = 1/12, B's 1-day work = 1/24. Combined 1-day work = 1/12 + 1/24 = 3/24 = 1/8. Therefore, they will complete the work together in 8 days.
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