A and B can complete a piece of work in 24 days and 30 days respectively. Working together, what fraction of the work can they complete in 4 days? MCQ with Answer and Explanation

A and B can complete a piece of work in 24 days and 30 days respectively. Working together, what fraction of the work can they complete in 4 days?
A. 1/5
B. 4/15
C. 7/20
D. 3/10
Answer: Option D
Solution (By JKSSB Mock Tests)
Total work = LCM(24, 30) = 120 units. Efficiency of A = 5, B = 4. Combined efficiency = 9 units/day. In 4 days, work completed = 4 * 9 = 36 units. Fraction of work completed = 36 / 120 = 3 / 10.

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Practice More Time and Work Questions

Question #1
A and B working separately can do a piece of work in 9 and 12 days respectively. If they work for a day alternately, A beginning, in how many days will the work be completed?
A. 11 days
B. 10(1/4) days
C. 10 days
D. 10(1/2) days

Correct Answer: Option B


Explanation:
Total work = LCM(9, 12) = 36 units. Efficiency of A = 4, B = 3. In 2 days (A + B), work done = 4 + 3 = 7 units. In 10 days (5 pairs of 2 days), work done = 7 * 5 = 35 units. Remaining work = 36 - 35 = 1 unit. On the 11th day, it is A's turn. Time taken by A to complete 1 unit = 1/4 day. Total time = 10 + 1/4 = 10(1/4) days.

This question belongs to: Maths Time and Work
Question #2
A can complete a work in 10 days and B can complete the same work in 20 days. If they work together, in how many days will the work be completed?
A. 6.67
B. 10.67
C. 8.67
D. 12.67

Correct Answer: Option A


Explanation:
Combined rate = 1/10 + 1/20. Time = 1 ÷ combined rate = 6.67 days.

This question belongs to: Maths Time and Work
Question #3
A, B and C can do a piece of work in 10, 15 and 30 days respectively. If they work on alternate days in the order A, B, C, in how many days will the work be completed?
A. 15 days
B. 12 days
C. 18 days
D. 20 days

Correct Answer: Option A


Explanation:
Total work = LCM(10, 15, 30) = 30 units. Efficiency of A = 3, B = 2, C = 1. In a 3-day cycle (A on day 1, B on day 2, C on day 3), work completed = 3 + 2 + 1 = 6 units. Number of cycles required = 30 / 6 = 5 cycles. Total days = 5 * 3 = 15 days.

This question belongs to: Maths Time and Work