A, B and C can do a piece of work in 10, 15 and 30 days respectively. If they work on alternate days in the order A, B, C, in how many days will the work be completed? MCQ with Answer and Explanation
A, B and C can do a piece of work in 10, 15 and 30 days respectively. If they work on alternate days in the order A, B, C, in how many days will the work be completed?
A. 12 days
B. 18 days
C. 15 days
D. 20 days
Answer: Option C
Solution (By JKSSB Mock Tests)
Total work = LCM(10, 15, 30) = 30 units. Efficiency of A = 3, B = 2, C = 1. In a 3-day cycle (A on day 1, B on day 2, C on day 3), work completed = 3 + 2 + 1 = 6 units. Number of cycles required = 30 / 6 = 5 cycles. Total days = 5 * 3 = 15 days.
A can do a piece of work in 10 days, B in 12 days and C in 15 days. They carry out the work together and get a total of Rs. 4500 as wages. Find the share of C.
Explanation:
Total work = LCM(10, 12, 15) = 60 units. Efficiency of A = 6, B = 5, C = 4. Ratio of wages = 6 : 5 : 4. Total ratio parts = 15. Share of C = (4 / 15) * 4500 = 4 * 300 = Rs. 1200.
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