A can do a piece of work in 10 days, B in 12 days and C in 15 days. They carry out the work together and get a total of Rs. 4500 as wages. Find the share of C. MCQ with Answer and Explanation

A can do a piece of work in 10 days, B in 12 days and C in 15 days. They carry out the work together and get a total of Rs. 4500 as wages. Find the share of C.
A. Rs. 1800
B. Rs. 1200
C. Rs. 1500
D. Rs. 1000
Answer: Option B
Solution (By JKSSB Mock Tests)
Total work = LCM(10, 12, 15) = 60 units. Efficiency of A = 6, B = 5, C = 4. Ratio of wages = 6 : 5 : 4. Total ratio parts = 15. Share of C = (4 / 15) * 4500 = 4 * 300 = Rs. 1200.

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Practice More Time and Work Questions

Question #1
A is 20% less efficient than B. If A can complete a work in 15 days, in how many days will B complete it?
A. 10 days
B. 9 days
C. 12 days
D. 11 days

Correct Answer: Option C


Explanation:
Let efficiency of B = 5, then efficiency of A = 4. Total work = Efficiency of A * Time of A = 4 * 15 = 60 units. Time taken by B = 60 / 5 = 12 days.

This question belongs to: Maths Time and Work
Question #2
If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:
A. 5 days
B. 7 days
C. 6 days
D. 4 days

Correct Answer: Option D


Explanation:
Total work = 10 * (6M + 8B) = 2 * (26M + 48B) => 60M + 80B = 52M + 96B => 8M = 16B => 1M = 2B. Total work in terms of boys = 10 * (6*2B + 8B) = 10 * 20B = 200 boy-days. Efficiency of 15 men and 20 boys = 15*2B + 20B = 50B. Time taken = 200 / 50 = 4 days.

This question belongs to: Maths Time and Work
Question #3
A can do a piece of work in 10 days, B in 15 days. They work together for 2 days and then A leaves. In how many days will B complete the remaining work?
A. 10 days
B. 11 days
C. 8 days
D. 12 days

Correct Answer: Option A


Explanation:
Total work = LCM(10, 15) = 30 units. Efficiency of A = 3, B = 2. Combined efficiency = 5 units/day. In 2 days, work completed = 2 * 5 = 10 units. Remaining work = 30 - 10 = 20 units. Time taken by B to complete remaining work = 20 / 2 = 10 days.

This question belongs to: Maths Time and Work