A and B working separately can do a piece of work in 9 and 12 days respectively. If they work for a day alternately, A beginning, in how many days will the work be completed? MCQ with Answer and Explanation

A and B working separately can do a piece of work in 9 and 12 days respectively. If they work for a day alternately, A beginning, in how many days will the work be completed?
A. 10 days
B. 10(1/2) days
C. 10(1/4) days
D. 11 days
Answer: Option C
Solution (By JKSSB Mock Tests)
Total work = LCM(9, 12) = 36 units. Efficiency of A = 4, B = 3. In 2 days (A + B), work done = 4 + 3 = 7 units. In 10 days (5 pairs of 2 days), work done = 7 * 5 = 35 units. Remaining work = 36 - 35 = 1 unit. On the 11th day, it is A's turn. Time taken by A to complete 1 unit = 1/4 day. Total time = 10 + 1/4 = 10(1/4) days.

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Practice More Time and Work Questions

Question #1
10 men can complete a work in 14 days. If 14 men work at the same rate, in how many days will the work be completed?
A. 12.0
B. 10.0
C. 16.0
D. 14.0

Correct Answer: Option B


Explanation:
Total work = 10 × 14 = 140 man-days. Required days = 140/14 = 10.0 days.

This question belongs to: Maths Time and Work
Question #2
A can complete a work in 18 days and B in 36 days. After working together for 5 days, what percentage of work remains?
A. 63.33
B. 58.33
C. 65.83
D. 60.83

Correct Answer: Option B


Explanation:
Remaining work = (1 - 5*(1/18+1/36))×100 = 58.33%.

This question belongs to: Maths Time and Work
Question #3
12 men can complete a work in 22 days. If 16 men work at the same rate, in how many days will the work be completed?
A. 18.5
B. 22.5
C. 16.5
D. 20.5

Correct Answer: Option C


Explanation:
Total work = 12 × 22 = 264 man-days. Required days = 264/16 = 16.5 days.

This question belongs to: Maths Time and Work